Table of Contents
Charging of Insulators
Since charge cannot flow through insulators, neither conduction nor induction can be used to charge, insulators, so in order to charge an insulator friction is used. Whenever an insulator is rubbed against a body exchange of electrons takes place between the two. This results in appearance of equal and opposite charges on the insulator and the other body. Thus the insulator is charged.
For example rubbing of plastic with fur, silk with glass causes charging of these things.
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Charging of Insulators
Last modified on:4 years agoReading Time:2Minutes Charging of Insulators Since charge cannot flow through insulators, neither conduction nor induction can be used to charge, insulators, so in order to charge an insulator friction is used. Whenever an insulator is rubbed against a body exchange of electrons takes place between the two. This results in appearance of…
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Charging by Contact
Last modified on:4 years agoReading Time:2Minutes Charging by Contact When a negatively charged ebonite rod is rubbed on a metal object, such as a sphere, some of the excess electrons from the rod are transferred to the sphere. Once the electrons are on the metal sphere, where they can move readily, they repel one another and…
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Charging by Rubbing
Last modified on:4 years agoReading Time:3Minutes Charging by Rubbing The simplest way to charge certain bodies is to rub them against each other. When a glass rod is rubbed with a silk cloth, the glass rod acquires some positive charge and the silk cloth acquires negative charge by the same amount. The explanation of appearance of…
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Work & Energy (LA)
Last modified on:5 years agoReading Time:22Minutes1. Define work, energy and power. Give the SI units for each of the these quantities. A man whose mass is 80 kg climbs up 30 steps of the stairs in 30 s. If each step is 12.5 cm in height, calculate the power used in climbing the stairs, (g =…
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Work & Energy (SA)
Last modified on:5 years agoReading Time:22MinutesShort Answer Type Questions-I (2 Marks) 1. The velocity of a body moving in a straight line is increased by applying a constant force F, for some distance in the direction of the motion. Prove that the increase in the kinetic energy of the body is equal to the work done…
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Work & Energy (VSA)
Last modified on:5 years agoReading Time:14Minutes1. Seema tried to push a heavy rock of 100 kg for 200 s but could not move it. Find the work done by Seema at the end of 200 s. [2017 (T-II)] 2. At what speed a body of mass 1 kg will have a kinetic energy of 1 J?…
