Table of Contents
Charging of Insulators
Since charge cannot flow through insulators, neither conduction nor induction can be used to charge, insulators, so in order to charge an insulator friction is used. Whenever an insulator is rubbed against a body exchange of electrons takes place between the two. This results in appearance of equal and opposite charges on the insulator and the other body. Thus the insulator is charged.
For example rubbing of plastic with fur, silk with glass causes charging of these things.
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Reynolds Number
Last modified on:3 years agoReading Time:10MinutesWhat is Reynolds Number? The Reynolds number (Re) is a dimensionless parameter used in fluid mechanics to characterize the flow of a fluid (liquid or gas) around an object or through a conduit. It relates the inertial forces to the viscous forces in the fluid and helps determine the type of…
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Extra Questions For Class 10 Maths Chapter 1 Real Numbers Based On The Fundamental Theorem of Arithmetic
Last modified on:3 years agoReading Time:6MinutesEvery composite number can be expressed (factorised) as a product of primes, and this factorisation is unique, apart from the order in which the prime factors occur. The prime factorisation of a natural number is unique, except for the order of its factors. ⊕ Property of HCF and LCM of two…
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Extra Questions For Class 10 Maths Chapter 1 Real Numbers Based On Rational Numbers and Their Decimal Expansions
Last modified on:3 years agoReading Time:1MinuteExtra Questions On Euclid’s Division Lemma Question:Without actually performing the long division, state whether the following rational numbers willhave a terminating decimal expansion or a non-terminating repeating decimal expansion: (i) 13 / 3125 (ii) 129 / 225775 (iii) 77 / 210 (iv) 14587 / 1250 (v) 833 / 225572 Related Posts
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Extra Questions For Class 10 Maths Chapter 1 Real Numbers Based On Irrationality of Numbers
Last modified on:3 years agoReading Time:3MinutesExtra Questions On Irrationality of Numbers Question: Prove that √5 is an irrational number. Solution: Let √5 is a rational number then we have √5=p/q, where p and q are co-primes. ⇒ p =√5q Squaring both sides, we get p2=5q2 ⇒ p2 is divisible by 5 ⇒ p is also divisible by…
