Table of Contents
Charging of Insulators
Since charge cannot flow through insulators, neither conduction nor induction can be used to charge, insulators, so in order to charge an insulator friction is used. Whenever an insulator is rubbed against a body exchange of electrons takes place between the two. This results in appearance of equal and opposite charges on the insulator and the other body. Thus the insulator is charged.
For example rubbing of plastic with fur, silk with glass causes charging of these things.
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Reynolds Number
Last modified on:3 years agoReading Time:10MinutesWhat is Reynolds Number? The Reynolds number (Re) is a dimensionless parameter used in fluid mechanics to characterize the flow of a fluid (liquid or gas) around an object or through a conduit. It relates the inertial forces to the viscous forces in the fluid and helps determine the type of…
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Chemistry MCQs for Class 11 Chapter-4 Chemical Bonding and Molecular Structure
Last modified on:4 years agoReading Time:27MinutesHere we are providing MCQ Questions for Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure. There questions are prepared by subject experts and are very useful for your exams. Practicing these questions will help you to score better marks in the exam. MCQ Questions for Class 11 Chapter 4…
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Chemistry MCQs for Class 11 Chapter – 3 Classification of Elements and Periodicity in properties
Last modified on:5 years agoReading Time:24Minutes Q.1. Periodic classification of elements is used to examine the(a) periodic trends in physical properties of elements(b) periodic trends in chemical properties of elements(c) Both (a) and (b)(d) None of the above Answer (c) Periodic classification of elements follow a logical consequence of electronic configuration of atoms which is used…
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Chemistry MCQs for Class 11 Chapter 2 Structure of Atom
Last modified on:5 years agoReading Time:26MinutesQ.1. Number of protons, neutrons and electrons in the element 89X231 is(a) 89, 89, 242 (b) 89, 142, 89(c) 89, 71, 89 (d) 89, 231, 89 Answer (b) Number of p = number of e– = 89 and neutrons 231 – 89 = 142. Q.2. Atoms with same mass number but…
