Charging of Insulators

  • Last modified on:5 years ago
  • Reading Time:2Minutes

Charging of Insulators

Since charge cannot flow through insulators, neither conduction nor induction can be used to charge, insulators, so in order to charge an insulator friction is used. Whenever an insulator is rubbed against a body exchange of electrons takes place between the two. This results in appearance of equal and opposite charges on the insulator and the other body. Thus the insulator is charged.

For example rubbing of plastic with fur, silk with glass causes charging of these things.

  • Charging of Insulators

    Last modified on:5 years agoReading Time:2Minutes Charging of Insulators Since charge cannot flow through insulators, neither conduction nor induction can be used to charge, insulators, so in order to charge an insulator friction is used. Whenever an insulator is rubbed against a body exchange of electrons takes place between the two. This results in appearance of…

  • Charging by Contact

    Last modified on:5 years agoReading Time:2Minutes Charging by Contact When a negatively charged ebonite rod is rubbed on a metal object, such as a sphere, some of the excess electrons from the rod are transferred to the sphere. Once the electrons are on the metal sphere, where they can move readily, they repel one another and…

  • Charging by Rubbing

    Last modified on:5 years agoReading Time:3Minutes Charging by Rubbing The simplest way to charge certain bodies is to rub them against each other. When a glass rod is rubbed with a silk cloth, the glass rod acquires some positive charge and the silk cloth acquires negative charge by the same amount. The explanation of appearance of…

  • RD Sharma Solutions for Class 9 Maths Chapter 13 Linear Equations in Two Variables

    Last modified on:6 years agoReading Time:51MinutesExercise 13.1 Question 1: Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case: (i) -2x + 3y = 12 (ii) x – y/2 – 5 = 0 (iii) 2x + 3y = 9.35…

  • IIT Foundation Mathematics Problems on Area and Perimeter

    Last modified on:5 years agoReading Time:6MinutesQ.1. If the sides of a triangle are 3 cm, 4 cm and 5 cm, then what is the radius of the circum-circle? Answer Answer: 2.5 cm Q.2. If the length of hypotenuse of a right angled triangle is 5 cm and its area is 6 sq cm, then what are…

  • IIT Foundation Mathematics Problems on Permutation and Combination

    Last modified on:5 years agoReading Time:4MinutesQ.1. Each section in first year of plus two course has exactly 30 students. If there are 3 sections, in how many ways can a set of 3 student representatives be selected from each section? Answer Answer: 27000 Q.2. How many numbers are there between 100 and 1000 such that every…

Leave a Reply

Join Telegram Channel

Editable Study Materials for Your Institute - CBSE, ICSE, State Boards (Maharashtra & Karnataka), JEE, NEET, FOUNDATION, OLYMPIADS, PPTs

Discover more from Gurukul of Excellence

Subscribe now to keep reading and get access to the full archive.

Continue reading