Check out the latest MCQ Questions on CBSE Class 12 Physics Chapter 4 Moving Charges and Magnetism. These questions are extremely helpful for CBSE Board Exams. NCERT Exemplar questions are also included. These concepts are not only important for the CBSE board exam but also are crucial for the competitive exams like JEE and NEET.
MCQs based on Moving Charges and Magnetism:
Q.1. Biot-Savart law indicates that the moving electrons (velocity v) produce a magnetic field B such that
(a) B ⊥ v.
(b) B || v.
(c) it obeys inverse cube law.
(d) it is along the line joining the electron and point of observation.
Answer
Answer: a(a) Magnetic field is given by
Where n is the direction of B which is in the direction of cross product of v and r. Or we can say that B is perpendicular to both v and r.
Q.2. Two charged particles traverse identical helical paths in a completely opposite sense in a uniform magnetic field B = B0k. [NCERT Exemplar]
(a) They have equal z-components of momenta.
(b) They must have equal charges.
(c) They necessarily represent a particle- antiparticle pair.
(d) The charge to mass ratio satisfy: (e/m)1+(e/m)2=0
Answer
Answer: dQ.3. A circular coil of radius 4 cm and of 20 turns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5 weber/m². The magnetic dipole moment of the coil is
(a) 0.15 ampere-m²
(b) 0.3 ampere-m²
(c) 0.45 ampere-m²
(d) 0.6 ampere-m²
Answer
Answer: bQ.4. The conversion of a moving coil galvanometer into a voltmeter is done by
(a) introducing a resistance of large value in series.
(b) introducing a resistance of small value in parallel.
(c) introducing a resistance of large value in parallel.
(d) introducing a resistance of small value in series.
Answer
Answer: aQ.5. An electron is projected with uniform velocity along the axis of a current carrying long solenoid. Which of the following is true? [NCERT Exemplar]
(a) The electron will be accelerated along the axis.
(b) The electron path will be circular about the axis.
(c) The electron will experience a force at 45° to the axis and hence execute a helical path.
(d) The electron will continue to move with uniform velocity along the axis of the solenoid.
Answer
Answer: d(d) F = -evB sin 180° = 0 (i.e 0= 0°or 180° in both cases F = 0). The electron will continue to move with uniform velocity or will go undeflected along the axis of the solenoid.
Q.6. In a cyclotron, a charged particle [NCERT Exemplar]
(a) undergoes acceleration all the time.
(b) speeds up between the dees because of the magnetic field.
(c) speeds up in a dee.
(d) slows down within a dee and speeds up between dees.
Answer
Answer: a (a) It is based on the fact that the electric field accelerates a charged particle and the perpendicular magnetic field keeps it revolving in circular orbits of constant frequency.Q.7. If a charged particle moves through a magnetic field perpendicular to it
(a) both momentum and energy of particle change.
(b) momentum as well as energy are constant.
(c) energy is constant but momentum changes.
(d) momentum is constant but energy changes.
Answer
Answer: cSince the direction of velocity of a particle varies so momentum changes but direction of magnetic force is always perpendicular to direction of charged particle. So no work is done, i.e. energy remains the same.
Q.8. A circular current loop of magnetic moment Mis in an arbitrary orientation in an external magnetic field B. The work done to rotate the loop by 30° about an axis perpendicular to its plane is [NCERT Exemplar]
(a) MB
(b) √3MB2
(c) MB2
(d) zero
Answer
Answer: d(d) The rotation of the loop by 30° about an axis perpendicular to its plane makes no change in the angle made by axis of the loop with the direction of magnetic field, therefore, the work done to rotate the loop is zero.
Q.9. A rectangular loop carrying a current i is situated near a long straight wire such that the wire is parallel to the one of the sides of the loop and is in the plane of the loop. If a steady current I is established in wire as shown in figure, the loop will
(a) rotate about an axis parallel to the wire.
(b) move away from the wire or towards right.
(c) move towards the wire.
(d) remain stationary.
Answer
Answer: cQ.10. A cubical region of space is filled with some uniform electric and magnetic fields. An electron enters the cube across one of its faces with velocity v and a positron enters via opposite face with velocity -v. At this instant,
(a) the electric forces on both the particles cause identical accelerations.
(b) the magnetic forces on both the particles cause equal accelerations.
(c) Only electron gains or looses energy.
(d) the motion of the centre of mass (CM) is determined by E alone.
Answer
Answer: bQ.11. Consider a wire carrying a steady current, I placed in a uniform magnetic field B perpendicular to its length. Consider the charges inside the wire. It is known that magnetic forces do not work. This implies that,
(a) motion of charges inside the conductor is unaffected by B, since they do not absorb energy.
(b) Some charges inside the wire move to the surface as a result of B.
(c) if the wire moves under the influence of B, no work is done by the force.
(d) If the wire moves under the influence of B, no work is done by the electric force on the ions, assumed fixed within the wire.
Answer
Answer: bQ.12. The maximum current that can be measured by a galvanometer of resistance 40 Ω is 10 mA. It is converted into voltmeter that can read upto 50 V. The resistance to be connected in the series with the galvanometer is
(a) 2010 Ω
(b) 4050 Ω
(c) 5040 Ω
(d) 4960 Ω
Answer
Answer: d
Q.13. Two identical current carrying coaxial loops, carry current I in an opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C,
(a) ∮CB.dl = ± 2µ0I.
(b) the value of ∮CB.dl is independent of sense of C. c
(c) there may be a point on C where, B and dl are parallel.
(d) B vanishes everywhere on C.
Answer
Answer: bAmpere’s law gives another method to calculate the magnetic field due to a given current distribution. Applying the Ampere’s circuital law, we have ∮CB.dl = i0(I – I) = 0 (because current is in opposite sense). Also, there may be a point on C where B and dl are perpendicular and hence ∮CB.dl = 0
Q.14. The strength of magnetic field at the centre of circular coil is
Answer
Answer: c(c) B = Field to circular portion
– Field due to straight portion
Q.15. A current carrying closed loop of an irregular shape lying in more than one plane when placed in uniform magnetic field, the force acting on it
(a) will be more in the plane where its larger position is covered.
(b) is zero.
(c) is infinite.
(d) may or may not be zero.
Answer
Answer: bA current carrying closed loop of any shape when placed in a uniform magnetic field does not experience any force.
Q.16. A current loop placed in a non-uniform magnetic field experiences
(a) a force of repulsion.
(b) a force of attraction.
(c) a torque but not force.
(d) a force and a torque.
Answer
Answer: dIn non-uniform magnetic field, current loop experiences an unequal opposite force which forms torque.
Q.17. If the beams of electrons and protons move parallel to each other in the same direction, then they
(a) attract each other.
(b) repel each other.
(c) no relation.
(d) neither attract nor repel.
Answer
Answer: bAs current carried by electrons and protons are in opposite direction.
Q.18. A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic field B, such that B is perpendicular to the plane of the loop. The magnetic force acting on the loop is
(a) irB.
(b) 2πriB
(c) zero
(d) πriB
Answer
Answer: cNet force on a current carrying closed loop is always zero, if it is placed in an uniform magnetic field.
Q.19. The gyro-magnetic ratio of an electron in an H-atom, according to Bohr model, is
(a) independent of which orbit it is in.
(b) neutral
(c) positive
(d) increases with the quantum number n.
Answer
Answer: aThe gyro-magnetic ratio is given by μl=−e2mL,L – Angular momentum of electron
Q.20. An electron is projected along the axis of a circular conductor carrying the same current. Electron will experience
(а) a force along the axis.
(б) a force perpendicular to the axis.
(c) a force at an angle of 4° with axis.
(d) no force experienced.
Answer
Answer: dSince electron is moving parallel to direction of magnetic field of the conductor Force (F) = qvB sin 0 = 0
Q.21. Three long, straight parallel wires, carrying current are arranged as shown in the figure. The force experienced by a 25 cm length of wire C is
(a) 10-3 N
(b) 2.5 × 10-3 N
(c) zero
(d) 1.5 × 3 N
Answer
Answer: cForce of repulsion by wire D and G on wire C is equal and opposite.
Q.22. What is the net force on the rectangular coil?
(a) 25 × 10-7 N towards wire.
(b) 25 × 10-7 N away from wire.
(c) 35 × 10-7 N towards wire.
(d) 35 × 10-7 N away from wire.
Answer
Answer: a
Q.23. In a circular coil of radius r, the magnetic field at the centre is proportional to
(a) r²
(b) r
(c) 1r
(d) 1r²
Answer
Answer: c
Q.24. A positive charge enters in a magnetic field and travels parallel to but opposite the field. If experiences
(a) an upward force.
(b) a downward force.
(c) an accelerated force.
(d) no force.
Answer
Answer: cForce of repulsion by wire D and G on wire C is equal and opposite.
Q.25. When a magnetic compass needle is carried nearby to a straight wire carrying current, then
(I) the straight wire cause a noticeable deflection in the compass needle.
(II) the alignment of the needle is tangential to an imaginary circle with straight wire as its centre and has a plane perpendicular to the wire
(a) (I) is correct
(b) (II) is correct
(c) both (I) and (II) are correct
(d) neither (I) nor (II) is correct
Answer
Answer: cQ.26. A strong magnetic field is applied on a stationary electron. Then the electron
(a) moves in the direction of the field.
(b) remained stationary.
(c) moves perpendicular to the direction of the field.
(d) moves opposite to the direction of the field.
Answer
Answer: bQ.27. In an inertial frame of reference, the magnetic force on a moving charged particle is F Its value in another inertial frame of reference will be
(a) remained same
(b) changed due to change in the amount of charge
(c) changed due to change in velocity of charged particle
(d) changed due to change in field direction
Answer
Answer: cQ.28. Which one of the following is correct statement about magnetic forces?
(a) Magnetic forces always obey Newton’s third law.
(b) Magnetic forces do not obey Newton’s third law.
(c) For very high current, magnetic forces obey Newton’s third law.
(d) Inside low magnetic field, magnetic forces obey Newton’s third law.
Answer
Answer: bQ.29. A charged particle is moving on circular path with velocity v in a uniform magnetic field B, if the velocity of the charged particle is doubled and strength of magnetic field is halved, then radius becomes
(a) 8 times
(b) 4 times
(c) 2 times
(d) 16 times
Answer
Answer: bQ.30. Two a-particles have the ratio of their velocities as 3 : 2 on entering the field. If they move in different circular paths, then the ratio of the radii of their paths is
(a) 2 : 3
(b) 3 : 2
(c) 9 : 4
(d) 4 : 9
Answer
Answer: bQ.31. A charged particle is moving in a cyclotron, what effect on the radius of path of this charged particle will occur when the frequency of the ratio frequency field is doubled?
(a) It will also be doubled.
(b) It will be halved.
(c) It will be increased by four times.
(d) It will remain unchanged.
Answer
Answer: dQ.32. Which of the following is not correct about cyclotron?
(a) It is a machine to accelerate charged particles or ions to high energies.
(b) Cyclotron uses both electric and magnetic fields in combination to increase the energy of charged particles.
(c) The operation of the cyclotron is based on the fact that the time for one revolution of an ion is independent of its speed or radius of its orbit.
(d) The charged particles and ions in cyclotron can move on any arbitrary path.
Answer
Answer: dQ.33. If an electron is moving with velocity ν produces a magnetic field B , then
(a) the direction of field B will be same as the direction of velocity ν.
(b) the direction of field B will be opposite to the direction of velocity ν.
(c) the direction of field B will be perpendicular to the direction of velocity ν.
(d) the direction of field B does not depend upon the direction of velocity ν.
Answer
Answer: cQ.34. Current flows through uniform, square frames as shown in the figure. In which case is the magnetic field at the centre of the frame not zero?
Answer
Answer: cQ.35. A moving coil galvanometer can be converted into an ammeter by
(a) introducing a shunt resistance of large value in series.
(b) introducing a shunt resistance of small value in parallel.
(c) introducing a resistance of small value in series.
(d) introducing a resistance of large value in parallel.
Answer
Answer: bQ.36. Two identical current carrying coaxial loops, carry current I in opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C, then which statement is correct?
(c) there may be a point on C where B and dl are
parallel.
(d) none of these
Answer
Answer: bQ.37. The correct plot of the magnitude of magnetic field B⃗ vs distance r from centre of the wire is, if the radius of wire is R
Answer
Answer: bQ.38. The nature of parallel and anti-parallel currents are
(a) parallel currents repel and antiparallel cur¬rents attract.
(b) parallel currents attract and antiparallel cur-rents repel.
(c) both currents attract. ’
(d) both currents repel.
Answer
Answer: bQ.39. The magnetic moment of a current I carrying circular coil of radius r and number of turns N varies as
(a) 1/r²
(b) 1/r
(c) r
(d) r²
Answer
Answer: dQ.40. Ampere’s circuital law is given by
Answer
Answer: bQ.41. A short bar magnet has a magnetic moment of 0. 65 J T-1, then the magnitude and direction of the magnetic field produced by the magnet at a distance 8 cm from the centre of magnet on the axis is
(a) 2.5 × 10-4 T, along NS direction
(b) 2.5 × 10-4 T along SN direction
(c) 4.5 × 10-4 T, along NS direction
(d) 4.5 × 10-4 T, along SN direction
Answer
Answer: bQ.42. A current carrying loop is placed in a uniform magnetic field. The torque acting on it does not depend upon
(a) area of loop
(b) value of current
(c) magnetic field
(d) None of these
Answer
Answer: dQ.43. In a moving coil galvanometer the deflection (Φ) on the scale by a pointer attached to the spring is
Answer
Answer: cAlso Check:
NCERT Solution of Moving Charges & Magnetism
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