Numerical Problems on Indirect Methods for Small Distances
Atomic Volume and Film Thickness
Apply volume formulas to estimate molecular dimensionsGiven the radius of one atom, $r = 2.5 \times 10^{-13}\text{ m}$.
The volume of a single atom (assuming it to be a sphere) is:
Number of atoms in 1 mole (Avogadro’s number), $N = 6.023 \times 10^{23}$.
Total volume of 1 mole of H-atoms:
Assuming that the film has one molecular thickness, the molecular size of the olive oil is equal to the thickness of the film ($t$).
Radius of drop $r = 0.25\text{ mm} = 0.025\text{ cm}$.
Radius of film $R = 10\text{ cm}$.
Radius of the oil drop, $r = 0.30\text{ mm} = 0.03\text{ cm}$.
Volume of the single drop ($V$):
Area of the rectangular film ($A$):
The molecular size (thickness $t$):
(Note: The textbook answer key provides $7.5 \times 10^{-7}\text{ cm}$. This is exactly 3 times the calculated value, implying the problem source likely intended for there to be 3 drops of oil, despite the prompt reading “A drop”.)
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