NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.2 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.2.

- Number Systems Class 9 Ex 1.1
- Number Systems Class 9 Ex 1.2
- Number Systems Class 9 Ex 1.3
- Number Systems Class 9 Ex 1.4
- Number Systems Class 9 Ex 1.5
- Number Systems Class 9 Ex 1.6

Board | CBSE |

Textbook | NCERT |

Class | Class 9 |

Subject | Maths |

Chapter | Chapter 1 |

Chapter Name | Number Systems |

Exercise | Ex 1.2 |

Number of Questions Solved | 4 |

Category | NCERT Solutions |

## NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.2

**Ex 1.2 Class 9 Maths Question 1.****State whether the following statements are true or false. Justify your answers.**

- Every irrational number is a real number.
- Every point on the number line is of the form , where m is a natural number.
- Every real number is an irrational number.

**Solution:****(1) True** (âˆµ Real numbers = Rational numbers + Irrational numbers.)**(2) False** (âˆµ no negative number can be the square root of any natural number.)**(3) False** (âˆµ rational numbers are also present in the set of real numbers.)

**Ex 1.2 Class 9 Maths Question 2.**

Are the square roots of all positive integers irrational? If not, give an example of the square root of a number that is a rational number.**Solution:**

No, the square roots of all positive integers are not irrational.

e.g.,

Here, â€˜4â€™ is a rational number.

**Ex 1.2 Class 9 Maths Question 3.**

Show how can be represented on the number line.**Solution:**

We know that, =

Draw of right angled triangle OQP, such that

OQ = 2 units

PQ= 1 unit

and âˆ OQP = 90Â°

Now, by using Pythagoras theorem, we have

OP^{2} = OQ^{2} +PQ^{2}= 2^{2} +1^{2}= op= =

Now, take O as center OP = 45 as radius, draw an arc, which intersects the line at point R.

Hence, the point R represents .

**Ex 1.2 Class 9 Maths Question 4.**

A classroom activity (constructing the â€˜square root spiralâ€™).**Solution:**

Take a large sheet of paper and construct the â€˜square root spiralâ€™ in the following fashion. Start with a point O and draw a line segment OP_{1} of unit length. Draw a line segment P_{1}P_{2} perpendicular to OP, of unit length (see figure).

Now, draw a line segment P_{2}P_{3} perpendicular to OP_{2}. Then draw a line segment P_{3}P_{4} perpendicular to 0P_{3}. Continuing in this manner, you can get the line segment P_{n-1}P_{n} by drawing a line segment of unit length perpendicular to OP_{n-1}. In this manner, you will have created the points P_{2}, P_{3}, â€¦.,P_{n}â€¦, and joined them to create a beautiful spiral depicting ,â€¦â€¦â€¦..

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