Case Study Questions for Class 11 Physics Chapter 2 Units and Measurements

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Home CBSE Class 11 Physics Case Study Qs Case Study Questions for Class 11 Physics Chapter 2 Units and Measurements
Case Study Questions for Class 11 Physics Chapter 2 Units and Measurements

Case Study Questions for Class 11 Physics Chapter 2 Units and Measurements

Case Study Questions

Question 1:

Measurement of Physical Quantity
All engineering phenomena deal with definite and measured quantities and so depend on the making of the measurement. We must be clear and precise in making these measurements. To make a measurement, magnitude of the physical quantity (unknown) is compared.
The record of a measurement consists of three parts, i.e. the dimension of the quantity, the unit which represents a standard quantity and a number which is the ratio of the measured quantity to the standard quantity.

(i) A device which is used for measurement of length to an accuracy of about 10-5m, is
(a) screw gauge
(b) spherometer
(c) vernier calipers
(d) Either (a) or (b)

(ii) Which of the technique is not used for measuring time intervals?
(a) Electrical oscillator
(b) Atomic clock
(c) Spring oscillator
(d) Decay of elementary particles

(iii) The mean length of an object is 5 cm. Which of the following measurements is most accurate?
(a) 4.9 cm
(b) 4.805 cm
(c) 5.25 cm
(d) 5.4 cm

(iv) If the length of rectangle l = 10.5 cm, breadth b = 2.1 cm and minimum possible measurement by scale = 0.1 cm, then the area is
(a) 22.0 cm2
(b) 21.0 cm2
(c) 22.5 cm2
(d) 21.5 cm2

(v) Age of the universe is about 1010 yr, whereas the mankind has existed for 106 yr. For how many seconds would the man have existed, if age of universe were 1 day?
(a) 9.2 s
(b) 10.2 s
(c) 8.6 s
(d) 10.5 s

Answer Answer:
(i) d
(ii) c
(iii) a
(iv) a
(v) c

Case Study Questions

Question 2:

A student was solving a physics problem where force is given in CGS units (dyne), and they were asked to convert it into SI units (newton). The student also had to verify the correctness of the formula:

$$
v=\sqrt{g R}
$$

Where $v$ is the velocity, $g$ is acceleration due to gravity, and $R$ is a length.

Q1. 1 dyne is equal to how many newtons?
(a) $10^{-3} \mathrm{~N}$
(b) $10^{-4} \mathrm{~N}$
(c) $10^{-5} \mathrm{~N}$
(d) $10^{-2} \mathrm{~N}$

Answer: (c) $10^{-5} \mathrm{~N}$

Q2. What are the dimensions of $v=\sqrt{g R}$ ?
(a) $\left[\mathrm{L} \mathrm{T}^{-1}\right]$
(b) $\left[\mathrm{L}^2 \mathrm{~T}^{-2}\right]$
(c) $\left[\mathrm{M} \mathrm{T}^{-2}\right]$
(d) $\left[\mathrm{LT}^2\right]$

Answer: (a) $\left[\mathrm{L} \mathrm{T}^{-1}\right]$
$\rightarrow g=\left[\mathrm{LT}^{-2}\right], R=[\mathrm{L}]$, so $\sqrt{ }\left(\mathrm{L}^2 \mathrm{~T}^{-2}\right)=\left[\mathrm{LT}^{-1}\right]$

Q3. What is the main limitation of dimensional analysis?
(a) It cannot verify units
(b) It cannot derive relations with trigonometric or exponential terms
(c) It is applicable only to SI units
(d) It does not work with scalar quantities

Answer: (b) It cannot derive relations with trigonometric or exponential terms

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