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Numerical Problems on Mobility of Charge Carriers
Mobility and Conductivity Practice Set
Apply $\mu = \frac{v_d}{E}$ and $\sigma = ne\mu$Potential difference $V = 4.5\text{ V}$, length $l = 0.1\text{ m}$, drift velocity $v_d = 1.5 \times 10^{-4}\text{ ms}^{-1}$.
First, calculate the electric field ($E$) across the conductor:
Now, compute the electron mobility ($\mu$) using the relation $\mu = \frac{v_d}{E}$:
Given $n = 8.5 \times 10^{28}\text{ m}^{-3}$, Current $I = 1\text{ A}$, Length $l = 0.24\text{ m}$, Area $A = 1.2\text{ mm}^2 = 1.2 \times 10^{-6}\text{ m}^2$, Potential difference $V = 3\text{ V}$, and charge of electron $e = 1.6 \times 10^{-19}\text{ C}$.
1. Calculate the drift velocity ($v_d$):
2. Calculate the electric field ($E$):
3. Calculate electron mobility ($\mu$):
Electron mobility $\mu_e = 0.54\text{ m}^2\text{V}^{-1}\text{s}^{-1}$, Hole mobility $\mu_h = 0.18\text{ m}^2\text{V}^{-1}\text{s}^{-1}$.
Carrier density $n_i = n_e = n_h = 3.6 \times 10^{19}\text{ m}^{-3}$.
Elementary charge $e = 1.6 \times 10^{-19}\text{ C}$.
The total conductivity ($\sigma$) of an intrinsic semiconductor is the sum of the conductivities due to electrons and holes:
Substitute the given values:
Rounding to three decimal places:
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